5x-16x^(1/2)+3=0

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Solution for 5x-16x^(1/2)+3=0 equation: 


D( x )

x < 0

x < 0

x in <0:+oo)

5*x-(16*x^(1/2))+3 = 0

5*x-16*x^(1/2)+3 = 0

t_1 = x^(1/2)

5*t_1^2-16*t_1^1+3 = 0

5*t_1^2-16*t_1+3 = 0

DELTA = (-16)^2-(3*4*5)

DELTA = 196

DELTA > 0

t_1 = (196^(1/2)+16)/(2*5) or t_1 = (16-196^(1/2))/(2*5)

t_1 = 3 or t_1 = 1/5

t_1 = 1/5

x^(1/2)-1/5 = 0

1*x^(1/2) = 1/5 // : 1

x^(1/2) = 1/5

x^(1/2) = 1/5 // ^ 2

x = 1/25

t_1 = 3

x^(1/2)-3 = 0

1*x^(1/2) = 3 // : 1

x^(1/2) = 3

x^(1/2) = 3 // ^ 2

x = 9

x in { 1/25, 9 }

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